Riddle

[IRPT]

Wonder where all the beer went?

[Hooligan]

quote:Originally posted by IRPT

Wonder where all the beer went?

The CAT HOUSE[:I]?

[JaxPT]

LOL sorry rolo, here this will keep ya busy:
I am always hungry,
I must always be fed,
The finger I lick
Will soon turn red.
What am I?

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placed above it makes greater things small. Placed beside it makes small things greater. In matters that counts it always comes first. Where others increase it keeps all things the same. What is it?

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there is a row a soldiers that is 1km in length. and they walk with a constant speed in a straight line, in 1 direction.
all the way at the end walks a messenger. he has to bring a message to the captain walking all the way at the beginning of the row

the messenger starts walking past the soldiers and immediately turns around when arriving at the captain and walks back to the end of the row. when the messenger is back at end. the whole group of soldiers traveled a distance of 1000 meters

the soldiers and captain are walking at the same constant speed. and the messenger (walking faster then the soldiers) is also walking a a constant speed. you don't know anything about time or speed
...

question. how many meters did the messenger travel. from the end of the row to the beginning and back.

[Rolo]

quote:Originally posted by JaxPT
placed above it makes greater things small. Placed beside it makes small things greater. In matters that counts it always comes first. Where others increase it keeps all things the same. What is it?

The number 1?

[Rolo]

quote:Originally posted by Hooligan

The CAT HOUSE[:I]?

LOL!

Hehe, that is "imported" beer...from Pittsburgh; Genny isn't available here.

[JaxPT]

yep got that one right rolo

[IRPT]

quote:Originally posted by JaxPT


I am always hungry,
I must always be fed,
The finger I lick
Will soon turn red.
What am I?

Fire

[Rolo]

Oh, good, IR! Glad you spared me, because I do not think I would have gotten that one.

[IRPT]

quote:Originally posted by JaxPT


there is a row a soldiers that is 1km in length. and they walk with a constant speed in a straight line, in 1 direction.
all the way at the end walks a messenger. he has to bring a message to the captain walking all the way at the beginning of the row

the messenger starts walking past the soldiers and immediately turns around when arriving at the captain and walks back to the end of the row. when the messenger is back at end. the whole group of soldiers traveled a distance of 1000 meters

the soldiers and captain are walking at the same constant speed. and the messenger (walking faster then the soldiers) is also walking a a constant speed. you don't know anything about time or speed
...

question. how many meters did the messenger travel. from the end of the row to the beginning and back.

2 KM

[JaxPT]

IR...dayummmmmmm...you got em both. I didnt expect the messenger one. The messenger has to have traveled 2 km. It doesn't matter what speed they walked at. At the beginning af the puzzle, the line is 1 km long. The general is therfore 1km ahead of him. He must therefore travel more than 1 km to reach the general. Since the line moves 1000 m, or 1 km forward, the end is where the beginning was. Even if he walked 1.5 km to the general, he only has to walk .5 km to get back to the end of the line. It goes faster going back, because now they are coming towards him, and not going away.
The calculated version:
Denote the speed of the line of soldiers by W and the speed of messenger by V. Let t1 denote the time it takes the messenger to reach captain and t2 the time it takes him to get back to the end of the line.The troop has travelled 1000m in time (t1+t2), so:

1000m = W (t1+t2)
t1+t2 = 1000m/W
At the same time both in time t1 and t2 the messenger travels 1000m relative to the column, so:
t1 = 1000m/(V-W)
t2 = 1000m/(V+W)
This gives equation: 1000m/W = 1000m/(V-W) + 1000m/(V+W) When you divide the numenators by 1000m, the denominators by W, and denote V/W by A you obtain: 1 = 1/(A-1) + 1/(A+1)
A^2 - 1 = 2A
Solving that quadratic formula for A you obtain 1+sqrt(2) and 1-sqrt(2). Since V/W can't be negative it turns out V/W = 1+sqrt(2).The distance travelled by the messenger is:
V (t1+t2) = V ( 1000m/(V-W) + 1000m/(V+W) ) = 1000m ( 1/(1-1/A) + 1/(1+1/A) )
After you plug in A and simplify:1000m ( 1+sqrt(2) )
and that is approximately 2414,21 m.